Placement Papers: AMI BIOS 24th Feb 2004 Kolkata

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Logical Reasoning:

  1. 3 types of chickens: Baby chickens cost 5 cents, hen chickens cost 3 dollares, rooster chickens cost 5 dollars. Buy 100 chickens for 100 dollars. How many will you have from each?
  2. Calculate: (x-a) (x-b) (x-c) ________ (x-z) ?
  3. What is the day after 4 days after 2 days before the day before tomorrow?
  4. 2 trains each of length 1 mile enter into 2 tunnels of lenth 1 mileand 2 miles apart. Speed if trains are 5 and 10 miles/hr. Give the postion as viewed by a helicopter when the trains meet?
  5. A says I, m not guilty B says C is not guilty C says A is not guilty If all above are true. Can we say anyone is guilty/innocent? Who is most likely to be guilty?
  6. 18 story building-Accountant, s office is 5 times the lawyer, s office. Architects office 2 floors up then he is halfway between Dentist, s & Accountant, s office. Architects office halfway down means betweenDentist, s and Lawyer, s office. Give the order
  7. How many tennis matches are to be arranged to conduct a tournament with 213 players?
  8. In a family 7 children don, t eat spinach, 6 don, t eat carrot, 5 don, t eat beans, 4 don, t eat spinach & carrots, 3 don, t eat carrot & beans, 2 don, t eat beans & spinach. 1 doesn, t eat all 3. Find the no. Of children. C/C ++
    1. void main () {char a [6] = “INDIA” while (⚹ a) {printf ( “% c” ⚹ a) ; a ++ ;} }
      1. india
      2. I N D I A
      3. no output
      4. error
      5. Null
    2. protected derivation
    3. int m = 10; main () {int m = 20; {int m = 30;} printf ( “% d % d” m, m) }
      1. 10 10
      2. 10 20
      3. 20 10
      4. 20 30
      5. 30 20
      6. None
    4. inline function is used to
      1. reduce program size
      2. reduce memory size
    5. void func (float newtotal) {newtotal = newtotal-2;} main () {float tot = 100.34; float sum = tot; sum ++ ; func (sum) ; cout <}
      1. 100.34
      2. 99.34
      3. 101.34
      4. 102.34
      5. None
    6. unsigned char snapnib (unsigned char misc) {int aloha, hamalo; hamalo = aloha = misc; misc = (hamalo ≪ 4) + ( (aloha & 0 × 0f) ≫ 4) ; return (misc) ;} main () {int getinp; unsig char getmisc; scanf ( “% x” &getinp) ; getmisc = snapnib (getinp & 0xff) ; printf ( “% x” getmisc) ;}
      1. Change line 4 to misc = (hamalo ≫ 4) + ( (aloha & oxof) ≪ 4)
      2. remove the 5
      3. Change line 4 to misc = (hamalo ≫ 4) + ( (aloha & oxfo) ≪ 4)
      4. Change line 11 to getmisc = snapnib (getinp)
      5. Nothing
    7. main () {int getinp = 6; while (--getinp) {printf ( “% d” getinp) ; if (getinp ++ ! = 3) ; else break; if (getinp--! = 5) continue; else getinp = getinp-2;} }
      1. 5421
      2. 5420
      3. 541
      4. 6543
      5. 5410
    8. unsigned char inn [2] = “5” int i, j = 0; sscanf (inn, “% d” &i) ; while (i) {i = i − 1; j ++ ; printf ( “% d” ++ j) ;}
      1. 14
      2. 12
      3. 24
      4. 35
      5. none
    9. char ⚹ fn (int number) {char a [] = “Amen” return (&a [number] ) ;} main () {int i; char ⚹ prechar; scanf ( “% d” &i) (input is 12) ; prechar = fn (i) ; printf ( “% c” ⚹ prechar) ;}
      1. a bus
      2. give string “Amen” as global
      3. use return (a [number] ) instead of return (&a [number] )
      4. give main before fn
    10. unsigned char u = 32767; unsigned char y = 32768; u = u + y; printf ( “% d” (signed char) , u)
      1. 65535
      2. -65535
      3. -1
      4. 1
      5. none
    11. ⚹ name = “ANYTHING” ⚹ foo = “ALRIGHT” ⚹ name1 = “WRONG” strcat (name, name1) ; printf ( “% s % s ⧵n” name, foo) ; return (0)
      1. ANYTHING WRONG? WRONG?
      2. ANYTHING
      3. ANYTHING WRONG? ALRIGHT
      4. ERROR
      5. NONE

Assembly

swap 2 variables without temp variables

(use XOR, OR, AND, NOT)

Developed by: