# Line slope calculator x+8y=33

**Straight line given by points A[1; 4] and B[9; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.125x+4.125

**Canonical form of the line equation:**x+8y-33 = 0

**Parametric form of the line equation:**

x = 8t+1

y = -t+4 ; t ∈ R

**Slope:**m = -0.125

**Slope angle of line: φ =**-7°7'30″ = -0.1244 rad

**X intercept:**x

_{0}= 33

**Y intercept:**y

_{0}= q = 4.125

**Distance line from the origin:**d

_{0}= 4.0931

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(8; -1)

**Normal vector: n =**(1; 8)

**Midpoint of the segment AB: M =**[5; 3.5]

**Perpendicular Bisector equation:**8x-y-36.5 = 0

**Vector OA = (1; 4) ; |OA| = 4.1231**

**Vector OB = (9; 3) ; |OB| = 9.4868**

**Scalar product OA .OB = 21**

**Angle ∠ AOB = 57°31'44″ = 1.0041 rad**