Placement Papers: Infosys Paper 300

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Infosys Paper 300

INFOSYS PLACEMENT PAPER ON 10th SEPTEMBER AT HYDRABAD

hi frends.

here are the questions

  1. (X) ^ - (X) 19 = 60 approach let (X) ^ = t so t- (t) ^ = 60 so now hit and trial the number which satisfies it is 64 so t = 64 so (X) ^ () = 64
  2. A cube problem which is painted with red is cut into 27 small cubes with six straight cuts
    1. how many cubes are there with 0 side red colour
    2. how many cubes are there with 1 side red colour
    3. how many cubes are there with 2 side red colour
    4. how many cubes are there with 3 side red colour
  3. A
  4. 0 faces coloured-1 (27- (12 + 6 + 8) )
  5. 1 faces coloured-6 (All middle ones are 1 face colored red 1 ⚹ 6 = 6)
  6. 2 faces coloured-12 (exclude corners other are 2 faces colored red so 4 ⚹ 3 = 12)
  7. 3 faces coloured-8 (all corners are 3 faces colored red so 2 at front and 2 at back)
  8. Approach draw a cube and cut it into 6 parts
  9. A man starts from XYZ city and drives a constant speed. After some time he sees a milestone with two digits written on it. After he drives for an hour, he sees another milestone with the same digits, but in reversed order. After another hour ofjourney, he sees another milestone with original digits but with a zero between them. Find the speed of the car? A let the distance showed on first milestone be 10x + y distance showed on second milestone be 10y + x now hit and trial let x = 1 y = 6 so 16,61, 106 distance is 45km/hr. This is the only condition satisfies
  10. A five digit no whose third digit is one greater than the sum of the first two digits and the third digit is double the fourth digit and fourth digit is double the fifth digit and second digit is greater than first digit by 5. And if we multiply fourth and fifth digith we get third digit. A Let the digits be denoted by p1p2p3p4p5 p3 = p1 + p2 + 1 p3 = 2p4 p4 = 2p5 p2 = p1 + 5 hit and trial 16842
  11. There was a cycle race going on. th of the those in front of a person and th of those behind him gives the total number of participants. How many people took part in the race? Let total number of people be x (x − 1) + (x − 1) = x so x = 31
  12. B and C initially speak English but when D joined Spanish they too took up Spanish. The only common language between A, B and E is French. The only common language between C and E is Italian. Three people speak Portuguese. Most common language is Spanish. One person knows all the 5 language, one person knows 4 languages, one person knows 3 languages, one person knows 2 languages and one person knows only one language. A-French, Spanish, Portuguese B-English, Spanish, French, Portuguese, Italian C-English, Spanish, Italian, Portuguese D-Spanish Approach draw table and solve it u will get it
  13. Uncle Reuben and aunt Cynthia came to town to shop. Reuben bought a suit and hat for $ 15. Cynthia paid as much as for her hat as Reuben did for his suit. Then she spent the rest of her money for her dress. On the way to home Cynthia called Reubens attention to the fact that his hat cost $ 1 more than her dress. Then uncle said if we had divided our hat money differently such that we bought a different hats mine costing 1 and times cost of yours then we would have spent the equal amount of money.
    1. How much the hat would cost in that case?
    2. What is the total amount spent?
  14. There was a match to be held. And 100 nations were to participate in that match. It was totally an elimination match, that is if a team loses a match it must be eliminated. Find out the total number of matches played to find out the grand winner? A very easy 99 matches just take example with 4teams T1, T2, T3, T4 T1 − T2 T1 won T2 eliminated T1 − T3 T3 won and T1 eliminated T3 − T4 T3 won and T4 eliminated so if there are totally 4 teams 3 matches are required to determine the winner if there are 100 teams total 99 matches are required.
  15. There were totally 100 men. 85 are married. 75 have T. V, 85 have radio, 70 have A. C. How many men have TV, radio, AC and also married? 85 are married so 15 are not married 75 have TV 25 dont have TV 85 have radio 15 dont have radio 70 have AC 30 dont have AC so totally 100- (15 + 25 + 15 + 30) = 15 have all
  16. One more question was some 11 names were given we have to find who is youngest

its a bit confusing draw the table and explain u will surely get the answer

English part is a bit easy and confusing also please concentrate on it.